4^2x-5=32^x+2

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Solution for 4^2x-5=32^x+2 equation: 



4^2x-5=32^x+2

We move all terms to the left:

4^2x-5-(32^x+2)=0

We get rid of parentheses

4^2x-32^x-2-5=0

We add all the numbers together, and all the variables

4^2x-32^x-7=0

We move all terms containing x to the left, all other terms to the right

4^2x-32^x=7

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